Why the index of array starts with 0

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Related Post : Why the index of array starts with 0

arrays - Why does the indexing start with zero in 'C
Array name is a constant pointer pointing to the base address.When you use arr[i] the compiler manipulates it as *(arr+i).Since int range is -128 to 127,the compiler thinks that -128 to -1 are negative numbers and 0 to 128 are positive numbers.So array index always starts with zero....
Last update Mon, 16 Jul 2018 10:23:00 GMT Read More

Why is array indexing in Java start with 0? - Stack Overflow
The index in an array is not really an index. It is simply an offset that is the distance from the start of the array. The first element is at the start of the array so there is no distance. Therefore the offset is 0....
Last update Fri, 13 Jul 2018 12:49:00 GMT Read More

Why Array Index starts from Zero - ALLInterview
Answer / ranga raj.b. Array is a chunk of continues memory allocation. The arthmetic that is used by compiler to move to the next array location is StartAddress + (Index)*sizeof(int)if it is an integer array.now if we see to access the first location of the array we have to give Index =0 and for next location index =1 and so onThis is why ...
Last update Thu, 05 Jul 2018 16:12:00 GMT Read More

Why array index in C starts with 0? - cs-Fundamentals.com
Why array index in C starts with 0? The array index in C starts with 0 because in C the name of an array is a pointer, which is a reference to a memory location. Therefore, an expression *(arr + n) or arr[n] locates an element n-locations away from the starting location because the index is used as an offset....
Last update Tue, 17 Jul 2018 09:46:00 GMT Read More